Solving for Time and Distance of a Rolling Ball

AI Thread Summary
To solve for the time it takes for a ball to fall from a height of 1.2 meters, the equation t = √(2y/g) can be used, where g is the acceleration due to gravity. For a height of 1.2 m, this results in a time of approximately 0.49 seconds. To find the horizontal distance the ball travels, the formula x = vt can be applied, using a horizontal speed of 1.5 m/s. This calculation yields a horizontal distance of about 0.74 meters. Thus, the ball will take approximately 0.49 seconds to reach the floor and land about 0.74 meters away from the bench.
kcc732
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Homework Statement



Chuck gives a horizontal speed v to a ball that then rolls off a lab bench y meters high. How long a time will it take the ball to reach the floor? How far from a point on the floor directlyt below the edge of the bench will the ball land? Calculate how long and how far for v=1.5 m/s and a bench height of 1.2 m.


Homework Equations



Vx=d/t? only horizontal component of velocity is relevant, right?

The Attempt at a Solution


confused
 
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The question definitely involves both horizontal and vertical motion.
Better write equations for the y part, too. Usually one for Vy and one for y suffice.
 
hey kcc
aight so when ur doing projectile motion try using this equation to find t:
t = √(2y/g)
and now that u have t u can use the formula V=x/t to find x or arrange it so that its x=vt
:D et voila'
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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