Projectile Velocity Analysis: Solving for Initial Vertical Velocity

AI Thread Summary
A soccer ball is projected at an angle, traveling a horizontal distance of 120 meters in 3 seconds, leading to a calculated horizontal velocity of 40 m/s. The initial vertical velocity was initially confusing, but the user realized it could be determined using the equation V2 = V1 + at, with gravity as the acceleration. By applying this formula, the initial vertical velocity was found to be 14.7 m/s upward. The discussion highlights the importance of understanding projectile motion equations in solving for various components of velocity. Overall, the user successfully solved the problem with assistance from the forum.
kayem
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Homework Statement



A Soccer ball is projected at a certain angle (ϴ) above the horizon. It travels a horizontal distance of 1.2x102m in 3.0s.

a) Find the horizontal velocity
b) Find the initial vertical velocity (VV1).
c) Find the magnitude and direction of the initial velocity (VI)

Homework Equations



V = d/t

VH = VIcosϴ
VV1 = VIsinϴ

(Subscript H denotes the horizontal axis and Subscript V denotes the vertical axis)

The Attempt at a Solution



I know how to do Part a):

dH = v/t
dH = 120 / 30
dH = 40 m/s [Forward]

Part b confuses me. It seems to me like there is some information missing that causes me to not be able to do it but the teacher has told me that all the information that I need is there. I'll be able to get part C if somebody can help me out with b).

This is Grade 12 Physics and I haven't taken Calculus yet.Thanks to anybody who can help me out.The answers on the sheet are:
a) 40 m/s
b) 15 m/s
c) 43 m/s [20o to the horizon]

Homework Statement

Thanks in advance for any help that you can give me!
 
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Well, right after I posted it, the answer hit me so never mind.

V2 = V1 + at
0m/s = V1 + (-9.81m/s2)(1.5s)
V1 = 14.7 m/s [up]Thanks anyways!
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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