1. The problem statement, all variables and given/known data A bird watcher meanders through the woods, walking 0.30 km due east, 0.65 km due south, and 2.25 km in a direction 37.0° north of west. The time required for this trip is 3.00 h. Determine the magnitude and direction (relative to due west) of the bird watcher's (a) displacement and 1 km (magnitude) 2° (direction north of west) (b) average velocity. 3 km/h (magnitude) 4° (direction north of west) Use kilometers and hours for distance and time, respectively. gravity: 9.8m/s^2 2. Relevant equations Vf = Vi + A(D)T (D)X = Vi(D)T + (A(D)T^2)/2 Vf^2 = Vi^2 + 2A(D)X 3. The attempt at a solution I drew a diagram and i still don't know what to do.