Projectiles dealing with a bullet

AI Thread Summary
To solve the projectile motion problem, the initial speed of the shell is 1.60 x 10^3 m/s at an angle of 56° to the horizontal. The horizontal range can be calculated by resolving the initial velocity into horizontal and vertical components using trigonometric functions. The time of flight can be determined using kinematic equations, specifically by calculating the vertical motion and applying the formula for time in the air. It is essential to use the horizontal distance formula, which relates distance, speed, and time. Properly applying these concepts will lead to the correct answers for both the horizontal range and the time of motion.
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1. Homework Statement
A shell is fired from the ground with an initial speed of 1.60*10^3m/s at an initial angle of 56° to the horizontal.
(a) Neglecting air resistance, find the shell's horizontal range.

(b) Find the amount of time the shell is in motion.



Homework Equations



vector triangle sin and cosine

The Attempt at a Solution


all of my answers have been wrong i did the triangle and got hyp 1600 opp side 1326.46 bottom 894.7 from there i don't know where to go please HELP
 
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You'll need to use the kinematic equations for projectile motion (horizontal and vertical components).
 
i know that i just can't figure out the horiz and vertical components is
vertical
Vi:1600
thats all i know
 
Would be better to:

1) Resolve the horizontal by doing Cos (theta) x initial velocity
2) v=u+at to get time in the air
3) Get horizontal component with trig like in 1)
4) distance bullet traveled is s = d / t rearranged to give d = s x t

That's all I can give you without giving you the answer on a plate :L
 
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