Proof/Explanation to why bullet hits the apple

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When a bullet is fired at an apple in free fall, both the bullet and the apple experience the same gravitational acceleration of -9.8 m/s². This means that as the bullet travels towards the apple, it falls at the same rate as the apple. If aimed correctly, the bullet will hit the apple because both objects descend together over time. In a hypothetical scenario in space, a bullet fired at an apple dropped simultaneously would also hit the apple at its original position after one second. The key reason for this is that gravity affects both the bullet and the apple equally, causing them to maintain their alignment throughout the fall.
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I have a bullet with a initial velocity and an apple in free fall (-9.8 acceleration). Whenever I shoot the bullet it will hit the apple as long as the vector of the bullet is aimed at the apple. What I want to know is why does that occur? Why is it that as long as I aim the apple, the bullet hits it?
 
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Is this a homework question? If so then you need to use the template.
 
No this is not really a home-work question? It's just a little question that I had. But I really need to know the answer.
 
OK, I have moved it from the homework section into the technical forums.
 
KingOfQuestions said:
I have a bullet with a initial velocity and an apple in free fall (-9.8 acceleration). Whenever I shoot the bullet it will hit the apple as long as the vector of the bullet is aimed at the apple. What I want to know is why does that occur? Why is it that as long as I aim the apple, the bullet hits it?
The top rated comment by CGP Grey under this video has a nice graphics explaining that:

 
The bullet and the apple fall at the same rate.

Imagine performing the experiment in space, let the apple go and simultaneously fire the gun at it from a range of 300 m with a bullet velocity of 300 m/s, the bullet will hit the apple at the apples original location 1 second later.

Now modify the experiment by adding the earth. 1 second after being dropped the apple will be 4.9 m below its original position, and the bullet will be 4.9 m below it's original trajectory for exactly the same reason. Gravity accelerated them both by the same amount for the same time, and so displaced them by the same distance.
 
comparing a flat solar panel of area 2π r² and a hemisphere of the same area, the hemispherical solar panel would only occupy the area π r² of while the flat panel would occupy an entire 2π r² of land. wouldn't the hemispherical version have the same area of panel exposed to the sun, occupy less land space and can therefore increase the number of panels one land can have fitted? this would increase the power output proportionally as well. when I searched it up I wasn't satisfied with...
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