Proof involving linear transformation of a set of vectors

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SUMMARY

The discussion centers on proving that if a set of vectors S = {u, v, w} in ℝⁿ is linearly dependent, then the transformed set {T(u), T(v), T(w)} in ℝᵐ is also linearly dependent, given that T is a linear transformation. The proof involves establishing a linear relationship among the vectors in S, represented as au + bv + cw = 0, where a, b, and c are not all zero. By applying the linear transformation T, it follows that T(au + bv + cw) = aT(u) + bT(v) + cT(w) = T(0) = 0, confirming the linear dependence of the transformed set.

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Lanthanum
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Homework Statement


Let T:\Re^{n}\rightarrow\Re^{m} and let S={u,v,w}\in\Re^{n}.

If S is linearly dependent, show that {T(u), T(v), T(w)} is also linearly dependent.

Homework Equations


N/A


The Attempt at a Solution


Since S\in\Re^{n} then S`\in\Re^{m}.
Not sure where to go from here
 
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If the set of vectors are dependent you can find a linear relationship between them.

What happens to this linear relationship under the map T?
 
If p(t) is the linear relationship between the vectors in S, does that mean that T[p(t)] is the linear relationship between the vectors in S`?

If so I guess that proves that S` is also linearly dependent since there exists the linear relationship T[p(t)] between its elements.
 
Look up the definition of linear dependence.
 
Something is lacking in your statement of the problem. Is T supposed to be a linear map? You did not say so.
 
Lanthanum said:
If p(t) is the linear relationship between the vectors in S, does that mean that T[p(t)] is the linear relationship between the vectors in S`?

If so I guess that proves that S` is also linearly dependent since there exists the linear relationship T[p(t)] between its elements.
Don't ask, work it out. Your "p(t) is the linear relationship" is what Ziox suggested you look up- the definition of "linearly dependent". If vectors, u, v, and w are linearly dependent, then there exist numbers, a, b, c, not all 0, such that au+ bv+ cw= 0.

Now look at T(au+ bv+ cw)= T(0).

As Arkajad suggested, you will need to specify that T is a linear transformation (which you do in a later post).
 
Aha! I think I have it.

If vectors, u, v, and w are linearly dependent, then there exist numbers, a, b, c, not all 0, such that au+ bv+ cw= 0.

Now look at T(au+ bv+ cw)= T(0)

Since T is a linear transformation, T(0)=0, and T(au+ bv+ cw)=aT(u)+bT(v)+cT(w)=0

Since there exists scalars, a, b, c, not all 0, such that the above equation is true, S` is linearly dependent.

I can't believe I missed that even after ZioX's advice, guess I needed a study break. Thanks guys.
 

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