- #1
heinerL
- 19
- 0
Can anybody help me with the following:
[tex]\lim_{n \rightarrow \infty} = \frac{1^k+2+k+...+n^k}{n^{k+1}}=\frac{1}{k+1}[\tex]
How do you proof this equation with the Riemann-integral, especially with upper/lower riemann sums?
thank you!
[tex]\lim_{n \rightarrow \infty} = \frac{1^k+2+k+...+n^k}{n^{k+1}}=\frac{1}{k+1}[\tex]
How do you proof this equation with the Riemann-integral, especially with upper/lower riemann sums?
thank you!