Proof of Fermat's Little Theorem for Prime p and Polynomial g(x) in Z_p[X]

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SUMMARY

The discussion centers on proving that for a prime p and an irreducible polynomial g(x) in Z_{p}[X], the equation [f(x)]^{k} = [f(x)] holds in the quotient ring Z_{p}[X]/(g(x)) for any polynomial f(x) in Z_{p}[X] and integer k > 1. Participants clarify that the proof is an extension of Fermat's Little Theorem (FLT) and discuss the nuances of adapting existing proofs for integers modulo p. The conversation highlights the need for precise definitions and understanding of the theorem's application in polynomial rings.

PREREQUISITES
  • Understanding of Fermat's Little Theorem (FLT)
  • Knowledge of polynomial rings, specifically Z_{p}[X]
  • Familiarity with irreducible polynomials in modular arithmetic
  • Basic concepts of quotient rings in abstract algebra
NEXT STEPS
  • Study the proof of Fermat's Little Theorem in detail
  • Explore properties of irreducible polynomials in Z_{p}[X]
  • Learn about quotient rings and their applications in algebra
  • Investigate examples of polynomial congruences in modular arithmetic
USEFUL FOR

Mathematicians, students studying abstract algebra, and anyone interested in number theory and polynomial equations in modular arithmetic.

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Homework Statement



For a prime p and a polynomial g(x) that is irreducible in Z_{p}[X], prove that for any f(x) in Z_{p}[X] and integer k > 1, [f(x)]^{k} = [f(x)] in Z_{p}[X]/(g(x)).


The Attempt at a Solution



I realize this is an extension of Fermat's Little Theorem, however I cannot figure out how to proceed. I attempted to adapt a proof of FLT for the integers modulo p, but couldn't get anywhere. Any nudges in the right direction would be greatly appreciated!
 
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Did you mean "there exists an integer k > 1" instead of "for every integer k > 1"?


What is the proof of FLT you're trying to adapt? What part of it doesn't work?
 
Yes, Hurkyl, I meant there exists an integer k > 1. Sorry about that.
 

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