Proof of the equation of gravational potential energy

In summary, the conversation discusses the equation for gravitational potential energy and the confusion surrounding its proof. The equation is U = -GMm/r, and it is derived using the formula W by gravity = GMm(1/r2 - 1/r1). The conversation also mentions the convention of choosing a reference point for potential energy at infinity, which makes the equation simpler. The concept of choosing a reference point for measurements, similar to choosing a point at rest when measuring velocity, is also mentioned. This convention is commonly used in other areas of physics, such as electrostatics.
  • #1
jwu
9
0

Homework Statement


All we know the gravitational potential energy is U=-GMm/r. But when I got confused when I was trying to understand the proof of this equation.



Homework Equations



Here's what they did:
W by grativity=GMm(1/r2-1/r1)
Therefore, since △Ugrav=-W by grav, we get
U2-U1=-GMm(1/r2-1/r1)
Let's choose out U=0 reference at infinity.that is , we decide to allow U2→0 as r2→infinity. Then this equation becomes U=-GMm/r


The Attempt at a Solution


Here's my question:
What does it mean by "Let's choose out U=0 reference at infinity.that is , we decide to allow U2→0 as r2→infinity. Then this equation becomes U=-GMm/r"?
Why the U2 would approach to 0 when r2 approached to infinity? And what ti U=0 reference?
Thank you!
 
Physics news on Phys.org
  • #2
We can't measure energy, only the difference between two states, just like velocity: Nobody can say "my velocity is 0". But you can say "my velocity is 0 with respect to ..."

So just like you assume something is at rest when measuring velocity (ex.: the ground, even though the Earth is moving w.r.t. the sun), you have to assume a point where energy is 0, no matter the one you choose. You just select the one that makes the equation "cleaner", which in this case is when r2 = infinity.
 
  • #3
It's a matter of convention.
When you solve a few problems about gravitational potential energy, you will see this is a good convention to follow.
You could have set U=0 at Earth's surface, but it will give you some trouble when solving equations.

The same convention is used in electrostactics, get used to it!
 

1. What is the equation for gravitational potential energy?

The equation for gravitational potential energy is: E = mgh, where E represents the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

2. How is gravitational potential energy related to the force of gravity?

Gravitational potential energy is directly related to the force of gravity. The higher an object is lifted, the more potential energy it has because the force of gravity acts on it over a greater distance, resulting in a greater potential energy.

3. Can the gravitational potential energy of an object be negative?

Yes, the gravitational potential energy of an object can be negative. This occurs when an object is located below the reference level, or the starting point for measuring potential energy. In this case, the potential energy is lower than the reference level and is considered negative.

4. How does distance affect the gravitational potential energy of an object?

The gravitational potential energy of an object is directly proportional to the distance between the object and the reference level. As the distance increases, the potential energy also increases. This means that the potential energy of an object at a greater height will be greater than the potential energy of an object at a lower height.

5. What are some real-life applications of the equation for gravitational potential energy?

The equation for gravitational potential energy is used in many real-life applications, such as calculating the potential energy of objects lifted by cranes or elevators, determining the energy required for objects to reach certain heights, and understanding the stability of structures like dams or roller coasters. It is also used in fields like astrophysics to study the potential energy of celestial bodies.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
587
  • Introductory Physics Homework Help
Replies
5
Views
1K
Replies
22
Views
1K
  • Introductory Physics Homework Help
Replies
15
Views
358
  • Introductory Physics Homework Help
Replies
23
Views
349
  • Introductory Physics Homework Help
Replies
5
Views
699
  • Introductory Physics Homework Help
Replies
3
Views
973
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
2
Replies
42
Views
3K
Back
Top