Proof that gamma matrices form a complete basis

joe_blogs
Messages
4
Reaction score
0
Hi all,

I'm interested in proving/demonstrating/understanding why the Dirac gamma matrices, plus the associated tensor and identity, form a complete basis for 4\times4 matrices.

In my basic QFT course, the Dirac matrices were introduced via the Dirac equation, and we proved various properties. After doing this, we were presented with this table:
<br /> \begin{tabular}{|c|c|c|} \hline<br /> Form of element &amp;Transforms as &amp;\# of components\\ \hline<br /> $\mathds{I}$ &amp;scalar &amp; 1 \\<br /> $\gamma^\mu$ &amp; vector &amp; 4 \\<br /> $\sigma^{\mu\nu}$ &amp; tensor &amp; 6 \\<br /> $\gamma^5\gamma^\mu$&amp; pseudo-vector &amp; 4 \\<br /> $\gamma^5$ &amp; pseudo-scalar &amp; 1 \\ \hline<br /> \end{tabular}
and told that these elements formed a complete basis for 4\times4 matrices. I've used this fact, and am now employing it in studying the effective weak Hamiltonian as part of an introduction to particle phenomenology. I'm now interested in understanding why it is true.

I've looked through these forums and my searching hasn't turned up a complete answer, or enough of a hint to figure it out. One suggestion I found involved showing the gammas form a Clifford algebra, which can be represented by the matrices over the quaternions. The suggestion was then that the move to matrices over the complex numbers involved the addition of the \gamma^5, but I don't know how to work out the detail here.

I'm happy to be directed to textbooks/online sources.

Thanks.

P.S. I'm a grad student, so while I don't have homework I guess I'll mention in the interests of full disclosure that this isn't any sort of assignment for credit, but rather something I want to grasp to further my understanding of a subject I am new to.
 
Physics news on Phys.org
Did you notice that 1+4+6+4+1 = 16 = 4 x 4 ?
Once you notice that, does it make sense that if those matrices are independent, they must form a complete basis ?
 
Ah, that's very simple. I guess I was stuck on the fact that the matrices have multiple dependencies between them. Because of that I was fixed on showing their span was the whole space. But obviously they're linearly independent so I don't need that...

Ok, thanks. ^_^
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
I am reading WHAT IS A QUANTUM FIELD THEORY?" A First Introduction for Mathematicians. The author states (2.4 Finite versus Continuous Models) that the use of continuity causes the infinities in QFT: 'Mathematicians are trained to think of physical space as R3. But our continuous model of physical space as R3 is of course an idealization, both at the scale of the very large and at the scale of the very small. This idealization has proved to be very powerful, but in the case of Quantum...
Thread 'Lesser Green's function'
The lesser Green's function is defined as: $$G^{<}(t,t')=i\langle C_{\nu}^{\dagger}(t')C_{\nu}(t)\rangle=i\bra{n}C_{\nu}^{\dagger}(t')C_{\nu}(t)\ket{n}$$ where ##\ket{n}## is the many particle ground state. $$G^{<}(t,t')=i\bra{n}e^{iHt'}C_{\nu}^{\dagger}(0)e^{-iHt'}e^{iHt}C_{\nu}(0)e^{-iHt}\ket{n}$$ First consider the case t <t' Define, $$\ket{\alpha}=e^{-iH(t'-t)}C_{\nu}(0)e^{-iHt}\ket{n}$$ $$\ket{\beta}=C_{\nu}(0)e^{-iHt'}\ket{n}$$ $$G^{<}(t,t')=i\bra{\beta}\ket{\alpha}$$ ##\ket{\alpha}##...

Similar threads

Back
Top