wabbit said:
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This can actually be extended to Aristarchus' calculation of the ratio of their distance (off by a factor 20 but only as a result of measurement imprecision), but this requires some geometry.
http://en.m.wikipedia.org/wiki/Aristarchus_of_Samos
It might work to go straight to drawing skinny right triangles, like Aristarchus. His way is not so abstract and you don't have to wait for an eclipse or accept other people's accounts and lore about eclipses. You can actually see for yourself that it is farther.
By spreading your arms to measure an angle and drawing a skinny triangle in the dirt.
Samos is an island just off the coast of what is now Turkey. Pythagoras was born and grew up on Samos.
The city Miletus was in sight on the mainland, across the bay. Thales was born in Miletus and was Aristarchus teacher.
On a half-moon late afternoon when the sun is nearly ready to set, the moon is still fairly high in the sky.
In the late afternoon, the next time there is an exact half moon, spread your arms and point with your right arm at the sun and your left at the moon. It's a big angle! Clearly more than 80 degrees, nearly a square corner!
At that moment you have a right triangle sun-moon-earth with the right angle at the moon, and a large angle at the earth. The insight is that the angle at the sun is small, so the triangle must be skinny.
Try drawing right triangles EMS with the right angle at M, and the angle at E really big, like your widespread arms, more than 80 degrees.
The only way the triangle can be is long skinny, with a very small angle at S
the distance ES has to be way longer than the distance EM
it's empirical about triangles, we
experience triangles. Let your daughter directly experience a right triangle the next afternoon there is an exact half moon high in the sky and the sun is down near the horizon.
Aristarchus got it right.