Suppose there is a researcher at a chemical company whose job is to create the compound barium phosphate. BaCl2*2H2O and (NH4)2HPO4 was mixed together in a water solution. However the compound that formed was not the desired Ba3(PO4)2 but Ba(HPO4). How can the researcher prepare the correct solution? Wanted reaction: 3BaCl2 + 2(NH4)2HPO4 --> Ba3(PO4)2 + 4NH4Cl + 2HCl Reaction in reality: BaCl2 + (NH4)2HPO4 --> Ba(HPO4) + 2NH4Cl Well, there would need to be a 3:2 ration of barium chloride and phosphate compound instead of 1:1. If there is a set M of 0.6 M for each reactant, the vol (L) can be changed so 5 L of BaCl2 yields 3 mol and 3.33 L of (NH4)2HPO4 yields 2 mol?? Are there other ways (changing M) to achieve the desired results? Thanks.