Properties of Complex Numbers (phasor notation)

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SUMMARY

The discussion centers on the derivation of the real and imaginary parts of complex numbers using phasor notation. The real part is defined as Real(A) = |A|cos(α), while the imaginary part is defined as Imag(A) = j|A|sin(α). These expressions are derived from Euler's formula, where e^(jα) = cos(α) + jsin(α) and e^(-jα) = cos(α) - jsin(α). The discussion clarifies how these equations are formulated through the manipulation of exponential functions.

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  • Understanding of complex numbers and their properties
  • Familiarity with Euler's formula
  • Basic knowledge of trigonometric functions
  • Ability to manipulate exponential expressions
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jeff1evesque
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1. Statement:
The Real Part of a "Complex Number is expressed as the following:
[tex]Real(A) = \frac{1}{2}(A + A*) = \frac{1}{2}(|A|e^{j\alpha} + |A|e^{-j\alpha}) = \frac{1}{2}|A|(2cos(\alpha)) = |A|cos(\alpha)[/tex]. (#1)

The Imaginary Part of a "Complex Number" is expressed as the following:
[tex]Imag(A) = \frac{1}{2}(A - A*) = \frac{1}{2}(|A|e^{j\alpha} - |A|e^{-j\alpha}) = \frac{1}{2}|A|(2jsin(\alpha)) = j|A|sin(\alpha)[/tex]. (#2)


2. Questions:
I was just curious how [tex]\frac{1}{2}|A|(2cos(\alpha))[/tex] was derived in equation (#1), and how [tex]\frac{1}{2}|A|(2jsin(\alpha))[/tex] was derived in equation (#2)?

thanks,


Jeff
 
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jeff1evesque said:
I was just curious how [tex]\frac{1}{2}|A|(2cos(\alpha))[/tex] was derived in equation (#1), and how [tex]\frac{1}{2}|A|(2jsin(\alpha))[/tex] was derived in equation (#2)?

e = cosα + jsinα
e-jα = cosα - jsinα

so e + e-jα = 2cosα
e - e-jα = 2jsinα
 

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