Comparing the Properties of CsF and NaF: Melting Point and Solubility

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The discussion centers on comparing the properties of sodium fluoride (NaF) and cesium fluoride (CsF), focusing on their solubility and melting points. NaF has a solubility of 0.042 kg/kg H2O and a melting point of 988°C, while CsF has a significantly higher solubility of 3.67 kg/kg H2O and a lower melting point of 682°C. The conversation highlights that the smaller ionic radius of NaF contributes to its higher melting point, as smaller ions are packed more closely, requiring more energy to separate them. In contrast, the weaker bonds in CsF, indicated by its lower melting point and higher solubility, suggest that the bond length in NaF is longer than in CsF. The discussion also touches on the importance of crystallization systems in understanding solubility differences.
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Hello, I am doing a grade 12 chemistry course, through independent learning and I am stuck on a question... its probably simple and my mind just doesn't want to work.. so hopefully someone could help me out.

I am given the info that NaF has a solubility of 0.042 kg/kg H20 at 25 C and a melting point of 988 C.
And that CsF has a solubility of 3.67 kg/kg H20 at 25 C and a melting point of 682 C.
So what would be the difference between the properties of CsF and NaF?
 
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NaF having a smaller radius could account for its higher boiling point. If an atom has a smaller radius, that means the elements are closer together, so more heat is needed to separate them.
 
Did u check whether the crystalization system is the same...?As for solubility,it has to do both with the length of the bonding and with the system of crystalization.

Danie.
 
Because CsF has a lower melting point and higher solubility than NaF, it means that the CsF bond is weaker than the NaF bond. This makes sense since the bond length for NaF is longer than CsF.
 
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