Proportionality calculations (Coulombs Law)

AI Thread Summary
Two unlike charges attract each other with a force of 5 x 10^-5 N when 12 cm apart. Using Coulomb's Law, the force increases as the distance decreases, specifically following an inverse square relationship. When the distance is reduced to 4 cm, the force can be calculated to be significantly higher than the initial force due to the reduced distance. Additionally, to achieve a force of 2.0 x 10^-4 N, the distance between the charges must be determined using the same inverse square principle. Understanding these calculations is essential for solving similar problems involving electrostatic forces.
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Two unlike charges attract each other with a force of 5 x 10^-5 when placed 12 cm apart.



1) What is the force between them when they are 4.0cm apart


2)At what distance apart will the force between them be 2.0 x 10^-4


now i have attempted these questions, but i cannot find a suitable method of solving these questions that is consistent with all types of these questions...
Can anyone be willing to show me a method of solving these types of questions.
 
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whitestrat said:
Two unlike charges attract each other with a force of 5 x 10^-5 when placed 12 cm apart.

1) What is the force between them when they are 4.0cm apart

2)At what distance apart will the force between them be 2.0 x 10^-4

now i have attempted these questions, but i cannot find a suitable method of solving these questions that is consistent with all types of these questions...
Can anyone be willing to show me a method of solving these types of questions.

you know Coulombs Law?

F = \frac { k q_1 q_2 }{r^2}

In this problem you have F = 5 x 10^-5 N if r = 5 cm. What would F be if r = 4.0 cm
 
yes i know coulombs law, its just the question is worked out using proportionality from coulombs law
 
Hi whitestrat,

Coulomb's law is an inverse square law, so, for example, if you double the distance between the charges the force decreases by a factor of four; if you halve the distance, the force increases by a factor of four.

Here the distance goes from 12cm to 4cm. So what happens to the force?
 
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