Propulsive force and force at interface

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The problem involves two blocks, one weighing 6 kg and the other 2 kg, with a horizontal force applied to the 6 kg block. The frictional force between the 6 kg block and the table is 18 N, while there is no friction for the 2 kg block. The blocks accelerate at 3 m/s², leading to a calculated propulsive force of 42 N on the 6 kg block. The force at the interface between the two blocks is determined to be 6 N, as it is the force required to accelerate the 2 kg block. Understanding the forces and their directions is crucial for solving such problems.
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Homework Statement


Two blocks, one of mass 6 kg and the other of mass 2 kg, are placed in contact on a horizontal table, and a constant horizontal force is applied to the 6 kg mass. There is a constant frictional force of 18 N between the 6 kg mass and the table, but no frictional force between the 2 kg mass and the table. the blocks accelerate at 3 m/s2.
a. what is the propulsive force applied to the 6 kg mass?
b. what is the force at the interface between the two blocks?

Homework Equations


F=ma

The Attempt at a Solution


I honestly have no idea where to start I have read the book and looked at my notes and I am not sure where to start.
Fnet=ma
fnet= F-18[/B]
 
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Start by drawing a large diagram on which you mark everything relevant. Examine it closely, looking for inspiration.

Post it here.
 
upload_2014-10-16_3-11-25.png
 
Now you can see what is going on!

Apply your Fnet = ma formula to the situation.
 
Fnet=mneta
F-18=mneta
F-18=(6+2)(3)
F-18=24
F=42N
 
is this correct?
 
That looks right.

Next, what force must be being applied to the 2kg body to cause it to be accelerating at this rate? (Remember, if you don't apply sufficient force to it it won't accelerate at this rate, and if you were to apply more than the required force it will accelerate faster.)
 
Will that force be the force at the interface. Since 2 kg mass experiences no friction
Fnet=ma
Fnet=2(3)
F=6N
 
Will that force be the force at the interface. Since 2 kg mass experiences no friction
Fnet=ma
Fnet=2(3)
F=6N
Yes that force can only come from the bigger mass pushing on that leading body.
 
  • #10
So a) what is the propulsive force applied to the 6kg mass? 42N
and b) what is the force at the interface between the two blocks? 6N
 
  • #11
It's always a good idea to associate a direction with the description of vector quantities (even when the direction may not be explicitly sought).

So, for each answer decide whether the horzontal force is directed to the right or the left.
 
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