Proton in Magnetic Field Problem

AI Thread Summary
To find the radius of a proton's circular path in a magnetic field, the relevant equations are F=qvB and Fc=mv^2/r. Given the proton's speed of 7.0 x 10^3 m/s and a magnetic field strength of 0.75 T, the charge of the proton is equal to that of an electron but is positive. The confusion arose from mixing up the charge value with the proton's mass, which was clarified in the discussion. Understanding these equations is crucial for solving the problem accurately.
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Homework Statement


A proton moves at a speed of 7.0 multiplied by 103 m/s as it passes through a magnetic field of 0.75 T. Find the radius of the circular path. Note that the charge carried by the proton is equal to that of the electron, but is positive.

Homework Equations


F=qvB
Fc=mv^2/r

The Attempt at a Solution


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Help!
 
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The digits of your charge value look suspiciously like those of the proton mass.
 
Oh wow. I can't believe I overlooked that. Thank you so much!
 

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