(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Using the definition of continuity show that f(x) = 2x^{2}+ 5 is continuous at x = 3

2. Relevant equations

3. The attempt at a solution

For all ε>0 there exists δ>0 such that |x-3|<δ implies that |2x^{2}+ 5 -23| = |2(x^{2}-9)| = |2(x+3)(x-3)| < |2(x+3)δ|

Could anybody give me advice as to where I should take it from here to show that |2x^{2}+ 5 -23|<ε

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# Homework Help: Prove 2x^2+5 is continuous at x=3

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