# Homework Help: Prove a^0 = 1 if a=/=0

1. Feb 9, 2008

### thinkies

1. The problem statement, all variables and given/known data

Prove that a^0 = 1 if a is not equal to 0.

2. Relevant equations

3. The attempt at a solution
Well,since a is not equal to 0, I replace it with another number.

(1^0)^0 = 1

(6^0)^0 = 1

ETC

Is this enough to prove that a^0 = 1 if a is not equal to 0.Even thought its a basic and easy question...im doubting.

Thx

2. Feb 9, 2008

### thinkies

hhmmm any1?...

3. Feb 9, 2008

### Dick

You haven't 'proved' anything. You just wrote down some numbers. What's your definition of a^x? If it's e^(log(a)*x) the answer is pretty easy, just take the log of both sides. To prove something you need a precise definition of the thing you are trying to prove. What does a^x mean?

4. Feb 10, 2008

### Dick

Are you just assuming the laws of exponents? Like (a^n)*(a^m)=a^(n+m)? If so, then set m=0 and solve for a^m.

5. Feb 10, 2008

### thinkies

Thanks, i though about doing that before, dunno what came up in mind.