Prove Convergence of Positive Series Squares

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Homework Statement



The infinite series defined by \Sigma a_{n}, with a_{n}>0 are convergent. If then the series defined by \Sigma a_{n}^{2} coverges, prove it!

Homework Equations



The relevant equations has been stated above.

The Attempt at a Solution



Since every term in the first infinite series are positive the partial sums are monotone increasing. And, since it converges these will be bounded above. Then it feels like the series of the squares will be bounded above as well. Since, due to convergence, every term approaches zero.

Is it correct to say that since the term a_{n} tends to zero as n tends to infinity, its square also will?

Are my reasoning correct? How am I supposed to do it formally?

So very grateful for hints!
 
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Apply the ratio test.
 
Ohh... I was making it harder than it actually was!

Thank you so much! :)
 
find out the sum of arithematic series which has 25 terms and its middle number is 20
 
harryjose said:
find out the sum of arithematic series which has 25 terms and its middle number is 20
Does this have anything at all to do with the original question?

Please, please, please do not "hijack" someone else's thread to ask your own question! It is very easy to start your own thread.
 
I can only speak for myself and I can't see the connection to my thread!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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