Prove/Find Counterexample: Intro to Set Theory

mbcsantin
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Homework Statement



Prove or find counterexamples. For any sets A, B, C in a universe U:

if A union C contained B union C then A contained B

Homework Equations



none.

The Attempt at a Solution



im just not sure if i did it right. id appreciate if you can check my work and let me know what changes i have to make. thanks

Let A be the empty set, and let B = C
Then A union C = B and
B union C = B so,
A union C contains B union C, but A does not contain B because A is the empty set and B is not.
 
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Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.
 
e(ho0n3 said:
Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.

alright. thank you so much!
 
e(ho0n3 said:
Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.

But what if I use the element proof for this..

Supposed that A is a subset of B.

Let x is an element of A u C.
therefore, x is an element of A and x is an element of C.
Since A is a subset of B by the definition of containment, x is an element of B.
Since x is an element of B and x is an element of C, we have x is an element of B u C. so any element of B u C is also in A u C. therefore, A u C is a subset of B u C.

Would this be right?
 
You are giving a counter example. You don't need a general proof, just any single counter example. You could just take A= {}, B= {1}, C= {1}.
 
mbcsantin said:
Let x is an element of A u C.
therefore, x is an element of A and x is an element of C.

No, that implies x is an element of A or x is an element of C.

Anyway, what you did here is irrelevant to your original question.
 
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