Prove two line elements represent the same space/plane

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SUMMARY

The discussion focuses on proving that the line element given by the equation ds² = a² (dη²/cosh⁴(η) + tanh²(η) dθ²) represents the same space as the 2-D Euclidean plane. The user attempts to find a coordinate transformation to express the line element in the form ds² = dx² + dy². They propose the transformations x = a tanh²(η) and y = aθ, leading to the derived expression ds² = 2a² tanh²(η) sech⁴(η) dη² + a² dθ², and consider the utility of the identity tanh²(η) + sech²(η) = 1 in their proof.

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Homework Statement


I've been given the line element given below in the relevant equations section and I need to prove that the space it represents is just the same as the 2-D Euclidean plane.

Homework Equations


ds^2 = a^2 \frac{d\eta ^2 }{cosh^4(\eta)} + a^2 tanh^2(\eta) d\theta ^2

Where
0\lt\theta\leq2\pi
0\lt\eta\leq\infty

The Attempt at a Solution


I'm pretty sure that to prove this I need to find the coordinate transform to show that the above line element should be equal to:
ds^2 = dx^2 + dy^2
So I believe I'm looking for x and y in terms of eta and theta, but I'm not entirely sure how to go about that.

Any suggestions are much appreciated!
 
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Okay well I can't seem to find a way to edit the original post so I'm going to reply with what I've got so far.
I've been looking at the trigonomic hyperbolic identities and their differentials.
If we have
## x = a tanh^2(\eta) ## then ## dx = 2tanh(\eta)sech^2(\eta)d\eta##
## y = a\theta ## then ## dy = ad\theta ##

This would then lead to ## ds^2 = 2a^2tanh^2(\eta)sech^4(\eta)d\eta^2 + a^2d\theta^2##
Where of course ## sech^4(\eta) = \frac{1}{cosh^4(\eta)}##

So it is sort of getting there, maybe.

Wondering if the fact that ##tanh^2(\eta)+sech^2(\eta) = 1 ## could be useful.
 

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