Prove uniqueness of solution to a simple equation

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Homework Statement



Prove that the equation e^x = 1+x admits the unique solution x_0 = 0.

2. The attempt at a solution

I think there should be a very simple proof based on monotonicity or the absence of inflection points, etc.

But I have no idea how to do it, and what theorems are to be used. All I can say from the equation, is that if there are solutions, they certainly satisfy

x>-1

I'm actually a little ashamed that I can't do this, most likely, trivial problem, maybe somebody can show me the right path?
 
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1+x is the tangent line to e^x at x=0 and e^x is concave up. Or note that if 1+x intersected e^x at another point then the Mean Value Theorem would say there is a point in between where the derivative of e^x is 1.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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