Proving 1/72 Not the Sum of Squares of Two Positive Integers

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1/72 cannot be expressed as the sum of the reciprocals of the squares of two different positive integers, as demonstrated through algebraic manipulation of the equation. The equation 72(b² + a²) = a²b² leads to a contradiction, confirming that such a representation is impossible. The discussion also shifts to exploring how to express 1/72 using the reciprocals of the squares of three different positive integers. Participants suggest starting with the equation 1/a² + 1/b² + 1/c² = 1/72 to investigate this further. Ultimately, the conversation emphasizes the challenge of the original problem while exploring alternative formulations.
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Homework Statement



Show that 1/72
cannot be written as the sum of the reciprocals
of the squares of two different positive integers.


Homework Equations





The Attempt at a Solution



Available solutions
1/8²-1/24²
1/9²+1/648
Therefore Proven.
 
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\frac{1}{a^2}+\frac{1}{b^2}=\frac{1}{72}

\frac{b^2+a^2}{a^2b^2}=\frac{1}{72}

72(b^2+a^2)=a^2b^2

Solve the equation and write here the solution.
 
Дьявол said:
\frac{1}{a^2}+\frac{1}{b^2}=\frac{1}{72}

\frac{b^2+a^2}{a^2b^2}=\frac{1}{72}

72(b^2+a^2)=a^2b^2

Solve the equation and write here the solution.

How do i solve that equation?
 
Move the terms from the left to the right side of the equation:

a^2b^2-72b^2-72a^2=0

Now factor out b2 or a2 and tell me what you got.
 
a^2=(72b^2)/(b^2-72)
 
icystrike said:
a^2=(72b^2)/(b^2-72)

Ok. Now what "a" is equal to? What can you conclude from the final solution?
 
Дьявол said:
Ok. Now what "a" is equal to? What can you conclude from the final solution?

Thanks for your help. But the actual problem is to derive the available solution from the question given.
 
Yes, that is what he is trying to show you how to do!

However, the problem, as you stated it was

"Show that 1/72 cannot be written as the sum of the reciprocals
of the squares of two different positive integers." (my emphasis)

You can't do that because, as you showed, it is not true.
 
HallsofIvy said:
Yes, that is what he is trying to show you how to do!

However, the problem, as you stated it was

"Show that 1/72 cannot be written as the sum of the reciprocals
of the squares of two different positive integers." (my emphasis)

You can't do that because, as you showed, it is not true.

I got it. I am sorry.

Now for part 2,
How can I write 1/72 with reciprocals of the squares of
three different positve integers.
 
Last edited:
  • #10
icystrike said:
I got it. I am sorry.

Now for part 2,
How can I write 1/72 with reciprocals of the squares of
three different positve integers.
Start by writing an equation that expresses this relationship.
 
  • #11
Mark44 said:
Start by writing an equation that expresses this relationship.

okay. 1/a^2+1/b^2+c^3=1/72
By studying the relationship of their factor,
The equation can be translated into :
1/x^2+1/(b^2)(x^2)+1/(c^2)(x^2)=1/72
Moreover,

b^2+c^2+1=x
 
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