Is A subset of B in this proof involving sets and integers?

  • Thread starter Thread starter Andrax
  • Start date Start date
AI Thread Summary
The discussion centers on proving that set A is a subset of set B, where A consists of elements defined by the formula involving pi and integers, and B is defined similarly with a different offset. The proof approach involves substituting elements from A into the expression for B. The participant initially struggled with the substitution but ultimately resolved the issue by expressing pi in terms of the elements of B. The solution confirmed that every element of A can indeed be represented in B, thereby validating the subset relationship. The proof is successfully completed by demonstrating the necessary transformations.
Andrax
Messages
117
Reaction score
0

Homework Statement



A = { pi + 2k pi / k \in Z }
B = {(- pi / 3) + (2k pi / 3 ) / k \in A }
Prove that A C B

Homework Equations


A C B = \forallXE E : x \ni A \Rightarrow X \ni B

The Attempt at a Solution


\ni[k E Z ]: x = pi + 2k pi
\ni[k E Z ]: x = pi ( 1 + 2k)
I'm sure i need to get a k and replace it with k' to prove that it belongs to B
 
Physics news on Phys.org
Edit : solved it by replacing pi by -pi/3+4pi/3 which led to the correct answer
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top