Proving a positive series converges

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Homework Statement



Let {an}n≥1 and {bn}n≥1 be strictly positive series.
If the limit n-> infinity (an/bn) = c /= 0, then the \sum an converges iff \sum bn converges, n≥1

Homework Equations





The Attempt at a Solution



Since we know that lim (an/bn) = c, then
for all ε>0, \exists a natural number N s/t for all n≥N,
|an/bn - c| < ε.

Then suppose the \sum an converges but the \sum bn does not...

I'm trying to understand what to prove exactly.. so IF the limit of (an/bn) = c, THEN the 2 series converge.. but it's confusing me since there is the second iff... what do I prove first?
Also any advice on how to go about it?
 
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You know that the is an N such that:
<br /> \frac{a_{n}}{b_{n}}-c&lt;1<br />
Hence
<br /> a_{n}&lt;(c+1)b_{n}<br />
What now?
 
Should I use comparison?
 
Yes, comparison is good.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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