Proving a Tangential Trig Identity

  • Thread starter Thread starter Char. Limit
  • Start date Start date
  • Tags Tags
    Identity Trig
AI Thread Summary
The discussion centers on proving the trigonometric identity tan^{-1}(\alpha) - tan^{-1}(\beta) = tan^{-1}\left(\frac{\alpha-\beta}{1+\alpha \beta}\right). Participants suggest using the relationship between the tangent function and the angles X and Y, where α = tanX and β = tanY. The identity simplifies to tan(X - Y) = (tanX - tanY)/(1 + tanXtanY), which confirms the original identity. The conversation highlights the connection between inverse tangent and tangent functions in proving the identity. Understanding this relationship is key to solving the problem.
Char. Limit
Gold Member
Messages
1,222
Reaction score
23

Homework Statement


I was reading on the Weierstrass substitution, and I came across the following trigonometric identity:

tan^{-1}(\alpha) - tan^{-1}(\beta) = tan^{-1}\left(\frac{\alpha-\beta}{1+\alpha \beta}\right)

Homework Equations



I'm not really sure which equations are applicable here.

The Attempt at a Solution



What my question is is "how is this proven?". And try as I might, I don't see a way to prove this. Any help would be deeply appreciated.
 
Physics news on Phys.org
Hi Char! :smile:

If α = tanX and β = tanY, it says tan(X - Y) = (tanX - tanY)/(1 + tanXtanY) :wink:
 
tiny-tim said:
Hi Char! :smile:

If α = tanX and β = tanY, it says tan(X - Y) = (tanX - tanY)/(1 + tanXtanY) :wink:

Hello tiny-tim!

Oh wow, it does. Thanks!
 
Back
Top