Proving (A U B) x (A U B) = (A x A) U (B x B) with Discrete Math

sallaboy
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Hello,

How do I proove :

(A U B) x (A U B) = (A x A) U (B x B)

if and only if : (A C B) or (B C A) ?

Please Advice,
Dimitry Haritonov
 
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Dear Tom,

First of all I need to proove the two sides.

so I've started with first side when ACB:

(a,b)E(AUB)x(AUB) => aE(AUB) and bE(AUB) => if ACB so AUB=B => aEB and bEB => (a,b)E(BxB)

the second side:

(a,b)E(AxA)U(BxB) => here I have a little problem, I don't sure that I can to state that: if ACB so (AxA)U(BxB) = (BXB).

If It's right, I can continue:

...(a,b)E(BXB)

and we got the same result by the two sides.

Please Advice,
Dimitry Haritonov
 
Dear Tom,

are there any ideas ?

Please Advice,
Dimitry Haritonov
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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