Proving a volume of a cylinder

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    Cylinder Volume
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The discussion focuses on proving the volume of a cylinder using the formula v = A^2 / (4πh), where h is the height and A is the area of the paper used to form the cylinder. Participants explore the relationship between the standard volume formula v = πr^2h and the new expression, attempting to manipulate the equations to derive one from the other. There is a mention of the curved surface area of the cylinder being related to the area of the paper. Some users express a preference for integral methods for clarity, while others seek clarification on specific terms and concepts. The conversation emphasizes the mathematical manipulation needed to connect the two volume equations.
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1. Show that a volume of a clyinder equals to v= A^2 \ (4πh)
where h= height of the cylinder
A = area of a original paper


how would i prove this question?
could anyone please help
thank you

v= πr^2 h -------1
v=A^2 \ (4πh)-----2

i tried to make h da subject but i got 4v^2 = Ar^2 which it does work out
 
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What is the curved surface area of a cylinder ?
Is it the area of paper used ?
 
yes the area of the paper is used
 
Since this is in the precalculus forum, i won't refer to integrals. The regular expression for the volume of a cylinder is nr^2h. The area of the paper is A. Find an expression for A in terms of n, r and h, and simply square that and divide by 4nh to show that this equals the volume of the sylinder.
 
Just for the record, I prefer the integral form, much nicer and easier to understant I find.

~H
 
thank you for your help though
 
what is the meaning of "putting the 2 functions in the parathesis separated by the colon" ?? :bugeye: :bugeye:
 
what's the meaning of
"A = area of a original paper"

yOU skipped the most important part !?
by folding a paper to form a cylinder !? I assume..
A=2πrh
V=πrrh = 2πrh2πrh\4πh = AA\4πh

@.u
 
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