Proving Divergence of ((-1)^m)m

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In summary, the conversation is about proving that the sequence ((-1)^m)m diverges, using the definition of convergence and considering the case where m=2M. The asker is seeking clarification on why m is greater than or equal to 1/2 when m=2M.
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Mathematicsresear
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Homework Statement


Prove sequence ((-1)^m)m diverges.

Homework Equations



for all epsilon greater than zero, there exists a natural number M such that for all natural numbers m greater than or equal to M, Ix_m-xI is less than or equal to epsilon.[/B]

The Attempt at a Solution



Assume it converges and consider epsilon to be 1/2, so there is an M such that I((-1)^m)m-LI is less than or equal to epsilon for all m greater than or equal to M. Now consider m to be 2M, Why is m greater than or equal to 1/2 for when m=2M? Just help me with this part, and not anything else, please.
 
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  • #2
Mathematicsresear said:
Why is m greater than or equal to 1/2 for when m=2M?

Did you mean to ask why ##(-1)^m m \ge 1/2## when ## m = 2M##?
 
  • #3
Stephen Tashi said:
Did you mean to ask why ##(-1)^m m \ge 1/2## when ## m = 2M##?
no
 

Related to Proving Divergence of ((-1)^m)m

What does "Proving Divergence of ((-1)^m)m" mean?

"Proving Divergence of ((-1)^m)m" refers to the mathematical process of showing that the sequence ((-1)^m)m, where m is a positive integer, does not converge to a specific value as m approaches infinity.

Why is it important to prove the divergence of a sequence?

Proving the divergence of a sequence allows us to understand the behavior of the sequence as the input value increases. It also helps us determine if the sequence has a limit or not, which can be useful in solving various mathematical problems.

What is the general approach to proving divergence of a sequence?

The general approach to proving divergence of a sequence is to show that the terms of the sequence are getting further and further away from each other as the input value increases, indicating that the sequence does not have a limit.

How can I prove the divergence of ((-1)^m)m?

To prove the divergence of ((-1)^m)m, you can show that the sequence alternates between positive and negative values, and as the input value m increases, the absolute value of the terms also increases. This indicates that the sequence does not have a limit and is therefore divergent.

Are there any specific techniques or methods for proving the divergence of ((-1)^m)m?

Yes, there are specific techniques such as the comparison test, limit comparison test, and the alternating series test that can be used to prove the divergence of ((-1)^m)m. It is important to carefully analyze the sequence and choose the appropriate test for a successful proof.

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