 #1
 1,011
 0
The problem asked to prove by contradiction that the function has only one real root. They used Roll'es theorem and proved that f ' (x) =/= 0 then they concluded that because f ' (x) =/= 0 then by contradiction the function can have atleast one real root...
Look at the picture it has the answer to the solution...
Question:
I dont understand the logic... I made up a graph where f ' (x) = 0 but yet f(x) still only has one real root.... so how is disproving that f'(x) can never equal zero prove that f(x) has atleast only one real root when I obviously showed a scenario in which f'= 0 but f only has one root
Look at the picture it has the answer to the solution...
Question:
I dont understand the logic... I made up a graph where f ' (x) = 0 but yet f(x) still only has one real root.... so how is disproving that f'(x) can never equal zero prove that f(x) has atleast only one real root when I obviously showed a scenario in which f'= 0 but f only has one root
Attachments

23.5 KB Views: 488