Proving Fourier Transform is Entire

fauboca
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g is continuous function, g:[-\pi,\pi]\to\mathbb{R}

Prove that the Fourier Transform is entire,

<br /> G(z)=\int_{-\pi}^{\pi}e^{zt}g(t)dt<br />

So,
G&#039;(z) = \int_{-\pi}^{\pi}te^{zt}g(t)dt=H(z).

Then I need to show that G(z) differentiable for each z_0\in\mathbb{C}.

I need to show \left|\frac{G(z)-G(z_0)}{z-z_0}-H(z_0)\right| &lt; \epsilon whenever 0&lt;|z-z_0|&lt;\delta, correct?

If that is correct, I am also having some trouble at this part as well.
 
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My guess is you can separate the real and imag part of G(z) and show that they satisfy Cauchy-Riemann equations
 
sunjin09 said:
My guess is you can separate the real and imag part of G(z) and show that they satisfy Cauchy-Riemann equations

How are the partials done? x and y and neglect t?
 
fauboca said:
How are the partials done? x and y and neglect t?

sure, t is a dummy variable, you are essentially exchanging differentiation over x,y and integration over t
 
sunjin09 said:
sure, t is a dummy variable, you are essentially exchanging differentiation over x,y and integration over t

So the C.R. equations are satisfied and that is it then?
 
What can be done to justify slipping differentiation past the integral?

How can I show the partials are continuous at this point?
 
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