Proving Geometry of Circle AD and BD Touching at A & B

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AD and BD touch the circle at points A and B, with AC parallel to BD. The discussion revolves around proving two equations: DF^2 = AF*EF and BF = DF. A participant initially struggles with proving DF = FB but later resolves the issue independently. There was a mention of an incorrect image upload, which hindered assistance. Ultimately, the problem was solved without further help from the forum.
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AD and BD touch the circule at points A and B
AC is parallel to BD
prove that:

1. DF^2 = AF*EF
2. BF = DF

its obvious that BF^2 = EF * AF i tried proving that DF = FB but with no luck.

edit: i uploaded the wrong picture earlier, terribly sorry i have so many of them :smile:
 

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anyone? :rolleyes:
 
I cannot see the image so I cannot help you out. If you are still stuck a faster way may be to send the image in an email and I could help you out then.
 
The attachment if you see is yet to be approved ...

-- AI
 
never mind guys i managed to solve it, thanks anyway :smile:
 

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