Proving H = S_4: Lagrange's Theorem

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Suppose that H is a subset of S_4, and that H contains (12) and (234). Prove that H=S_4.

The order of S_4 is 24.

(12)(234) = (1342) shows that the finite subset of group H is closed under the group operation, so it is a subgroup of H.

Then, using Lagrange's Theorem, |S_4:H|=24/2 = 12. so the order of H is 12 by this.

And now I am lost on how I can prove that H = S_4.
 
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math_nerd said:
Suppose that H is a subset of S_4, and that H contains (12) and (234). Prove that H=S_4.

There is something wrong here. The problem, as stated, is false. Did you mean that H has to be a subgroup of S_4? Because this is probably true...
 
* H is a subgroup.

And how is this true? I'm pretty lost on how to show this.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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