Proving if a function is a valid probability distribution

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SUMMARY

The function P_{k} = \frac{20}{5^{k}} for k ≥ 2 is a valid probability distribution if it satisfies the conditions 0 ≤ P_{k} ≤ 1 and the sum of probabilities equals 1. Specifically, proving that \sum_{k=2}^\infty \frac{20}{5^k} = 1 confirms its validity. A function is not a valid probability distribution if any of the following conditions fail: P_{k} < 0 for any k, P_{k} > 1 for any k, or \sum_{k=2}^\infty \frac{20}{5^k} ≠ 1.

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kioria
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Hi,

Given the function:

P_{k} = \frac{20}{5^{k}} for k \geq 2

How would you prove that P is a probability distribution? I would think that you prove that P is bounded by 0 and 1 (i.e., 0 \leq \Sigma P_{k} \geq 1)

And I guess the leading question is how you would prove that a function is not a probability distribution?
 
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You also need that
\sum_{k=2}^\infty\frac{20}{5^k}=1
 
You would prove that a function is NOT a valid probability distribution by showing that at least one of those conditions is not true. That is, that
1) Pk < 0 for some k or
2) Pk > 1 for some k or
3) \sum_{k=2}^\infty\frac{20}{5^k}\ne 1
 
Cheers
 

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