Proving Isomorphism of G to Subgroup of G/H + G/K

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SUMMARY

The discussion centers on proving that a group G is isomorphic to a subgroup of the direct product G/H + G/K, where H and K are normal subgroups of G with H intersect K = {e}. The mapping defined as f: G to G/H + G/K by f(g) = (gH, gK) is established as a homomorphism. The proof demonstrates that the kernel of f is trivial, confirming that f is injective, and thus by the First Isomorphism Theorem, G is isomorphic to a subgroup of G/H + G/K. The participants clarify the conditions under which this isomorphism holds.

PREREQUISITES
  • Understanding of group theory concepts, specifically normal subgroups.
  • Familiarity with the First Isomorphism Theorem in abstract algebra.
  • Knowledge of coset multiplication and its properties.
  • Experience with homomorphisms and their proofs in group theory.
NEXT STEPS
  • Study the properties of normal subgroups in group theory.
  • Learn about the First Isomorphism Theorem and its applications.
  • Explore the concept of direct products in group theory.
  • Investigate examples of isomorphic groups and their subgroup structures.
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This discussion is beneficial for students and researchers in abstract algebra, particularly those studying group theory, normal subgroups, and isomorphisms. It is also useful for educators looking to clarify concepts related to group homomorphisms and their proofs.

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Homework Statement


Let H and K be normal Subgroups of a group G s.t H intersect K = {e}. Show that G is isomorphic to a subgroup of G/H + G/K.


Homework Equations


G/H+G/K= direct product of G/H and G/K.


The Attempt at a Solution



Proof/
Lets define are mapping f:G to G/H+G/K by f(g)=(gH,GK). Need to show that this is a homomorphism. Obviously f is a well defined function (Do I need any more explanation here?). Operation Preserving- Let x,y be elements of G. Then f(xy)= (xyH,xyK)= (xHyH,xKyK)= (xH,XK),(yH,yK)=f(x)f(y) ( I need help justifying my step on this)
Thus f is a homomorphism. Since kerf ={g element of G| (gH,gK)=(H,K)}, then ker f={e}. Thus f is injective (one to one).
So By 1st isomorphism theorem, G/Ker f is isomorphic to f(G). Since f(G) is a subgroup of G/H+G/K (since f is one to one), then G is isomorphic to a subgroup of G/H + G/K (since G/Kerf= G because kerf={e}, is this right?)
My question is for clarification, does this seem like I have proven that G is isomorphic to a subgroup of G/H + G/K, or I have I proven that G is isomorphic to G/H + G/K ?
 
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Your proof looks good. A general rule of thumb for well-definedness is that you only need to be concerned when your domain involves picking representative elements of cosets (and then whether the function is independent of representative). In this case you're not, only the codomain involves cosets so you're OK.

For the homomorphism part, where are you stuck? Let's look at it slowly

f(xy)= (xyH,xyK) This is how f is defined

= (xHyH,xKyK) This is by definition of multiplication by cosets

= (xH,XK),(yH,yK) This is by the definition of multiplication for the product of two groups

=f(x)f(y) this is by the definition of f again

Then once you have that kerf is trivial, G/kerf = G is isomorphic to the image of f by the first isomorphism theorem. As to whether G is isomorphic to G/H + G/K, this will only be true if the image of f is all of G/H + G/K. Is this always true?
 
Office_Shredder said:
Your proof looks good. A general rule of thumb for well-definedness is that you only need to be concerned when your domain involves picking representative elements of cosets (and then whether the function is independent of representative). In this case you're not, only the codomain involves cosets so you're OK.

For the homomorphism part, where are you stuck? Let's look at it slowly

f(xy)= (xyH,xyK) This is how f is defined

= (xHyH,xKyK) This is by definition of multiplication by cosets

= (xH,XK),(yH,yK) This is by the definition of multiplication for the product of two groups

=f(x)f(y) this is by the definition of f again

Then once you have that kerf is trivial, G/kerf = G is isomorphic to the image of f by the first isomorphism theorem. As to whether G is isomorphic to G/H + G/K, this will only be true if the image of f is all of G/H + G/K. Is this always true?

Thanks for the help, I just needed some clarification.
 

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