Proving Lebesque Measure of {x^2 : x€E} is 0

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Suppose that E has Lebesque measure 0. Prove that the set {x^2 : x€E} has Lebesque measure 0.

Please help me. I have a problem which is unsolveable for me. Thanks!
 
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Do you know a "change of variables" formula that expresses the measure of the set {x^2 : x in E} as an integral on E ?
 
Honestly i have no idea about "change of variables" formula.I try to prove with outer measure formula but i failed.In my method i have difficulties about whether x^2 is subset of E or not. I made cases for it and for x^2 subset of E i made it but i think they can be disjoint sets.That is my failure point because i have no idea about this case.
 
change of variables ... you have a "nice" map \phi that maps a set E onto a set F, and a function f defined on F . How to relate integrals involving f[/itex] on F and f \circ \phi on E ?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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