Proving Limsup of AUB = Limsup(A) U Limsup(B)

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Homework Statement



Given A = {An} and B = {Bn}. Prove that Limsup ({AUB}) = Limsup(A) U Limsup(B).

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The Attempt at a Solution



The result of both sides is a set, so I attempted to use double inclusion to prove it. Used the definition of limsup, but didn't manage to prove that for x in limsup(AUB), it is either in limsup(A) or limsup(B) and vice versa.
 
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Do you know a formula for the lim sup of a sequence of sets, expressed in terms of unions and intersections?
 
You could use the following:
x is in limsup A if and only if x is in An for infinitely many n.

Then x is in \limsup{A\cup B}, if it is in infinitely many A_n\cup B_n. But then it must of course be in infinitely many An or Bn; thus x is in \limsup A_n\cup \limsup B_n.
The other implication is the same thing...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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