Proving M_{0i} = 0 in Special Relativity

TrifidBlue
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http://books.google.com/books?id=qhDFuWbLlgQC&lpg=PP1&pg=PA11#v=onepage&q&f=false"

lpha%20=0}^{3}%20\sum_{\beta%20=0}^{3}M_{\alpha%20\beta%20}(\Delta%20x^\alpha)(\Delta%20x^\beta).gif


Until he arrives at eq. 1.5

gif.latex?\large%20\Delta%20\grave{S}^2%20=%20\phi(v)\Delta%20S^2.gif


I don't understand the steps, can anyone explain it?

thanks
 
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I can't view the book through the link.
 
You can download it as PDF [deleted copyright-violating link - bcrowell]
Or as djvu file [deleted copyright-violating link - bcrowell]
 
The solution isn't to give us links to illegal online copies.

How about just writing out the details of the argument for us?
 
Have you tried showing M_{0i} = 0 yourself? If you can do that, the rest follows quite naturally but I should probably point out that this is a homework problem (its an exercise at the end of the chapter).
 
bcrowell, I'm sorry, for putting _illegal online copies.

WannabeNewton, I'll try again, I didn't notice it was an exercise. thanks.
 
WannabeNewton said:
Have you tried showing M_{0i} = 0 yourself? If you can do that, the rest follows quite naturally but I should probably point out that this is a homework problem (its an exercise at the end of the chapter).

I figured it out, thanks for your help :D
 
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