Proving Null Spaces and Transformations

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Homework Statement


Let T:V  W be a linear transformation. Prove the following results.

(a) N(T) = N(-T)
(b) N(T^k) = N((-T)^k)
(c) If V = W and t is an eigenvalue of T, then for any positive integer k
N((T-tI)^k) = N((tI-T)^k) where I is the identity transformation

The Attempt at a Solution


(a) for every x in V:
If T(x) = y, then –T(x) = -y
So then, T(0) = 0 = -T(0)
Is this right? On the right track?

I’m not sure how to approach the rest of them?

Thanks for your help!
 
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a) is right. b) is done essentially the same way. If Tkx = y, then (-T)kx = ___? It should be pretty easy. c) follows immediately from b).
 
AKG said:
a) is right.
Well, everything he said is right, but he hasn't proven what he set out to prove: that N(T) and N(-T) are equal sets.
 
Sorry, my mistake. Hurkyl is correct, redyelloworange has not yet answered part a) fully.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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