Proving Nullspaces: Null(M) = Null((M^T)(M)) | Matrix Homework

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To prove that Null((M^T)(M)) equals Null(M) for an mxn matrix M, it is established that Null(M) is a subset of Null((M^T)(M)). The challenge lies in demonstrating the reverse inclusion, starting with a vector x in Null((M^T)(M)), which satisfies M^T(M(x)) = 0. If M(x) is zero, the proof is complete; however, the discussion raises the question of what occurs for non-zero x where M^T(x) = 0. The conversation emphasizes the need to explore the implications of these conditions to finalize the proof. The equality of the nullspaces is crucial for understanding the properties of the matrix M.
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Homework Statement



Given an mxn matrix M, prove that Null((M^T)(M)) = Null(M)

Where M^T is the transpose of the matrix M.

The Attempt at a Solution



I was able to get the first part (Null(M) is a subset of Null((M^T)(M))), but I'm just having trouble proving the other way around. I pick any vector in Null((M^T)(M)), but unsure of what to do after that.
 
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The standard way to prove that to sets, A and B, say, are equal is to prove A is a subset of B then prove that B is a subset of A. And you prove A is a subset of B by starting "if x is in A" and then use the properties of A and B to conclude "x is in B".

Here, the two sets are Null(M) and Null(M^T(M)). If x is in Null(M) then M(x)= 0. It then follows immediately that M^T(Mx)= M^T(0)= 0. That's the easy way. If x is in Null(M^T(M)) then M^T(M(x))= 0. Obviously, if M(x)= 0 we are done. What can you say about non-zero x such that M^t(x)= 0?
 
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