Proving Quadrilateral PQRS is a Parallelogram

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To prove that quadrilateral PQRS is a parallelogram, the discussion focuses on the relationship between angles formed by the angle bisectors PO and QO. The sum of angles in the pentagon formed by points P, Q, R, and S is established as 540 degrees. By analyzing triangle QOP, the relationship between angles leads to the conclusion that 2a equals the sum of angles R and S. A new method for solving the problem is shared, providing an alternative approach to the original book solution. The conversation highlights the collaborative effort in finding multiple solutions to the geometric problem.
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Recently, I bought a book and found a strange question :

In the given figure, PQRS is a quadrilateral. PO and QO are bisectors of angle P and angle Q respectively, then prove that angle QOP = 1/2 (angle R + angle S)

I made several attempts to get the solution but failed. I guess, we need to prove that PQRS is a parallelogram.
 

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Write out the sum of angles of the yellow pentagon.

ehild
 

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It's 540 degrees.
 
physics kiddy said:
It's 540 degrees.

OK. How is the angle a related to p/2 and q/2? What is the sum of angles of the pentagon in terms of a, p/2, q/2, r and s?

ehild
 
Last edited:
In triangle QOP, determine angle QOP, hence determine reflex angle QOP.
 
Physics kiddy disappeared...

p/2+q/2=180-a (triangle)
p/2+q/2+r+s+360-a=540 (pentagon) -->

180-a+r+s+360-a=540, 2a=r+s.

ehild
 
Thank you ! Thank you again. I disappeared because I found the solution in a book. But you wrote a completely new and easy method to solve this question. Now, I have got two ways to solve this question.
 
I would like to see that solution from the book so much! Could you please show it?:smile:

ehild
 
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