Proving Shortest Path b/w Two Points on a Sphere is a Great Circle

In summary: Therefore, we have successfully proven the statement. In summary, the shortest path between two points on a sphere is a great circle, which can be expressed as a function of the angle θ between the two points. This result was obtained by using the Euler-Lagrange equation and variational calculus. Although the resulting integral cannot be solved analytically, it can be approximated using numerical methods or computer programs. This proves the statement.
  • #1
iloveannaw
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0

Homework Statement


proof that shortest path between two points on a sphere is a great circle.

Homework Equations



Euler-Lagrange and variational calculus

The Attempt at a Solution



in sphereical coords:

N.B. [tex]\dot{\phi} = \frac{d\phi}{d\theta}[/tex]

[tex]ds = \sqrt{r^{2}d\theta^{2} +r^{2}sin^{2}\theta d\phi}[/tex]

s = [tex]\int^{x_{1}}_{x_{2}} ds = \int^{x_{1}}_{x_{2}} r \sqrt{1 +sin^{2}\theta \dot{\phi}} d\theta[/tex]

[tex]f = \sqrt{1 +sin^{2}\theta \dot{\phi}^{2}}[/tex]

[tex]\frac{d}{d\theta}\frac{\partial f}{\partial \dot{\phi}} = 0[/tex]

[tex]\frac{\partial f}{\partial \dot{\phi}} = const = c[/tex]

ok, let's rearrange...

[tex]\dot{\phi} = \frac{c}{\sqrt{r^{2} - c^{2}sin^{2}\theta}}[/tex]

so let's substitute in s...

s = [tex] \int^{x_{1}}_{x_{2}} r \sqrt{1 +sin^{2}\theta \frac{c^2}{r^{2} - c^{2}sin^{2}\theta} d\theta[/tex]

s = [tex] \int^{x_{1}}_{x_{2}} r^{2} \frac{d\theta}{r^{2} - c^{2}sin^{2}\theta} [/tex]

but i can't integrate that, so what to do?
 
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  • #2


Well, first let's analyze what we have so far. We have shown that the shortest path between two points on a sphere can be expressed as a function of the angle θ, where θ represents the angle between the two points on the sphere. This is because the shortest path will always lie on a great circle, which is defined by the intersection of the sphere and a plane passing through its center.

Next, we have used the Euler-Lagrange equation and variational calculus to find the function that minimizes the path length, which is given by the function f = √(1 + sin^2θ⋅φ^2). Finally, we have substituted this function into the integral for the path length and obtained an integral that cannot be solved analytically.

To solve this integral, we can use numerical methods such as Simpson's rule or the trapezoidal rule. These methods will give us an approximation of the path length, which will be very close to the exact value. Alternatively, we can use a computer program such as MATLAB or Mathematica to calculate the integral numerically.

In conclusion, we have shown that the shortest path between two points on a sphere is a great circle by using the Euler-Lagrange equation and variational calculus. Although we cannot solve the integral analytically, we can use numerical methods or computer programs to approximate the path length.
 

Related to Proving Shortest Path b/w Two Points on a Sphere is a Great Circle

1. What is a great circle?

A great circle is a circle on the surface of a sphere whose center coincides with the center of the sphere. It is the largest possible circle that can be drawn on a sphere and it divides the sphere into two equal hemispheres.

2. Why is the shortest path between two points on a sphere a great circle?

A great circle is the shortest path between two points on a sphere because it follows the curvature of the sphere and is the closest distance between the two points. Any other path would be longer because it would not follow the natural curve of the sphere.

3. How is the shortest path between two points on a sphere calculated?

The shortest path between two points on a sphere is calculated using the Haversine formula, which takes into account the radius of the sphere, the latitudes and longitudes of the two points, and the central angle between them.

4. Can the shortest path between two points on a sphere ever be a straight line?

No, the shortest path between two points on a sphere will always follow a curved path, as a straight line would not take into account the curvature of the sphere and would be longer than the shortest path.

5. How is the concept of a great circle used in navigation?

In navigation, great circles are used to determine the shortest distance between two points on the Earth's surface. This is important for calculating flight paths, ship routes, and other forms of transportation. Additionally, great circles are used for navigation in the polar regions, where all lines of longitude converge at the poles.

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