Proving Singular Matrix A Has Nonzero Matrix B: Linear Algebra Problem

Braka
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The problem is prove that for every square singular matrix A there is a nonzero square matrix B, such that AB equals the zero matrix.

I got AB to equal the identity matrix, but not the zero matrix.
 
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Yeah, that would be bad, because that would imply that A is nonsingular. Anyway, think about what singularity implies for the columns of A.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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