Proving that a matrix is an inverse of another.

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Homework Statement



Let A be an m x n matrix, and suppose there exist n x m matrices C and D such that CA = In and AD = Im. Prove that C = D.

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The Attempt at a Solution



I think it's obvious that C=D=A^(-1). But I'm having trouble proving it since I cannot prove that A is a square matrix and I'm not sure how where to start trying to prove it if A is not square.
 
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Well, WLOG assume that m <= n.

If AD = Im, then what does that say about A? That means for any m-dimensional vector b, there is an n-dim vector x such that Ax = b (since one can choose x = Db). What does that say about the number of pivot rows of A?

If CA = In, that means for any n-dimensional vector b, there is an m-dim vector x such that A^Tx = b (one can choose x = C^Tb). What does that say about the number of pivot rows of A^T? What does that say about the number of pivot columns of A?

Then put those together. :)
 
Well, WLOG assume that m <= n.

If AD = Im, then what does that say about A? That means for any m-dimensional vector b, there is an n-dim vector x such that Ax = b (since one can choose x = Db). What does that say about the number of pivot rows of A?

If CA = In, that means for any n-dimensional vector b, there is an m-dim vector x such that A^Tx = b (one can choose x = C^Tb). What does that say about the number of pivot rows of A^T? What does that say about the number of pivot columns of A?

Then put those together. :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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