Proving That Any Vector in a Vector Space V Can Be Written as a Linear Combination of a Basis Set

kregg87
Messages
5
Reaction score
1

Homework Statement


Show that any vector in a vector space V can be written as a linear combination of a basis set for that same space V.

Homework Equations


http://linear.ups.edu/html/section-VS.html
We are suppose to use the 10 rules in the above link, plus the fact that if you have a lineraly independent set
{X1,X2,...,Xn} then -> c1X1+c2X2+...+cnXn = 0 vector implies that all the constants (c1,c2, etc) are zero.

Not looking for a complete solution, just not sure where to start. I've tried proof by contradiction and a couple other ways and non have worked out for me.

The Attempt at a Solution

 
Physics news on Phys.org
kregg87 said:

Homework Statement


Show that any vector in a vector space V can be written as a linear combination of a basis set for that same space V.

Homework Equations


http://linear.ups.edu/html/section-VS.html
We are suppose to use the 10 rules in the above link, plus the fact that if you have a lineraly independent set
{X1,X2,...,Xn} then -> c1X1+c2X2+...+cnXn = 0 vector implies that all the constants (c1,c2, etc) are zero.

Not looking for a complete solution, just not sure where to start. I've tried proof by contradiction and a couple other ways and non have worked out for me.

The Attempt at a Solution


Define "basis". (I know the usual definition, but what is the one YOU are using?)
 
Ray Vickson said:
Define "basis". (I know the usual definition, but what is the one YOU are using?)
My definition is a linearly independent set of N vectors, where N in the dimension of the space. My definition of dimension, N, is it the max number of mutually lineraly independant vectors possible.
 
kregg87 said:
My definition is a linearly independent set of N vectors, where N in the dimension of the space. My definition of dimension, N, is it the max number of mutually lineraly independant vectors possible.
So what can you say about a given vector? Can it be linearly independent from your basis? Or otherwise, what does it mean it can't?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top