Proving the half-life of Potassium-40

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AI Thread Summary
The discussion focuses on calculating the half-life of Potassium-40 (K-40) based on its decay rate. A sample with 4.0x10^18 nuclei emits 68 β-particles and photons per second, leading to the conclusion that the half-life is 1.3x10^9 years. The user initially struggles with the calculations, using the equations A=λN and T1/2 = ln2/λ but miscalculates the half-life in seconds. After receiving guidance, they realize the need to convert their result from seconds to years. The conversation highlights the importance of unit conversion in radioactive decay calculations.
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Homework Statement



"K-40... decays by two radioactive processes. It can decay by electron capture or β- emission.

It is found that a sample containing 4.0x10^18 nuclei of K-40 emits a total of 68 β- particles and photons each second. This shows the half life is 1.3x10^9 years."

Use the data in the passage to show that the half life is 1.3x10^9 years.

Homework Equations



I'm assuming...

T1/2 = ln2/λ; A=λN; A=A0e^(-λ)(t)

The Attempt at a Solution



Using A=λN --> A/N=λ --> (68)/(4*10^18) = 1.7^10-17
then ln2/(1.7^10-17) = 4.1*10^16 ->> waayy too big.

I then tried various other combinations of the above, but to no success.

Please help! I know I'm missing something VERY obvious.
 
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You calculated (correctly) the half-life in seconds. Now convert to years.
 
phyzguy said:
You calculated (correctly) the half-life in seconds. Now convert to years.

D'oh!

You legend, thank you :D
 
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