Proving the Identity Matrix Property: A^2=A for n-Rowed Matrices | 20 Marks

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please help me prove this...

Homework Statement



Show that If "A" is an n-rowed matrix that satisfies A^2=A Then:
Row(A)+Row(I-A)=n

Homework Equations





The Attempt at a Solution


well since A is n-rowed that means that its an n*n matrix so Ax=I
as i guess so :
Row(A)=Rank(A)
Rank(I-A)+nullity(I-A)=Rank(A)+nullity(A)=n
please help if i find its solution I will be given 20 mark for it and i have been trying to solve it for over two day :S
 
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Examining the eigenvales might help, note that:
<br /> Ax=\lambda x\Rightarrow A^{2}x=\lambda Ax\Rightarrow Ax=\lambda^{2}x<br />
I am not too sure what you mean by Row(A)
 


Multiply
A (I-A) and solve it. what does that tell you?
 


Thanks A lot guys I have proved it with your help :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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