Proving the Laplace Operator in Polar Coordinates

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To prove the Laplace operator in polar coordinates, start by using the chain rule to express the partial derivatives of U with respect to x and y in terms of ρ and θ. The transformation involves calculating the first and second derivatives of U with respect to these new variables. It is essential to apply the chain rule correctly, particularly when finding the second derivatives. No specific function U is required; the proof relies on the properties of differentiable functions. Understanding the relationships between the variables is crucial for successfully completing the proof.
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calculus--differentiation Help Please!

if x=\rho cos \theta and y=\rho sin \theta

prove that if U is a twice differentiable function of x and y that
\frac{\partial^2U}{\partial x^2} + \frac{\partial^2 U}{\partial y^2} = \frac{\partial^2 U}{\partial \rho^2} + \frac{1}{\rho}\frac{\partial U}{\partial \rho} + \frac{1}{\rho^2}\frac{\partial^2 U}{\partial \theta^2}

I have absolutely no clue how to get started on this one.

thanks
 
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anyone...
 
Try using the chain rule to find \frac{\partial U}{\partial\theta}. The do it agian to find the second derivatives. Hope it works!
 
I could try this except for the fact that i do not know what U equals...is there some assumption i am supposed to make here
 
No assumption. Just use \frac{\partial U}{\partial \theta } = \frac{\partial U}{\partial x} \frac{\partial x}{\partial \theta}+ \frac{\partial U}{\partial y} \frac{\partial y}{\partial \theta}
 
its messy!
 
i'm sorry i don't quite understand what i am supposed to be doing here. can i get a some explanation as to how and why to start this. i have really no idea here. thanks
 
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