Proving the Least Upper Bound Property: A Mathematical Inquiry

ssayan3
Messages
15
Reaction score
0
Least Upper Bound proof...

Homework Statement


Suppose A is a nonempty set that has x as an upper bound. Prove that x is the least upper bound of the set A iff for any E>0 there exists a y in A such that y>x-E


Homework Equations


None


The Attempt at a Solution


The forward where you assume that x is the least upper bound is very easy, but I'm having some trouble proving the reverse...

This is what I have so far...

Let x be an upper bound of A, and choose a point z in A.
If x is an upper bound of A, then x+z is also an upper bound.
 
Physics news on Phys.org


To prove the reverse, you are given that x is an upper bound for A having the property:

If \epsilon &gt; 0 there is a y in A satisfying x - \epsilon < y

You have to show that no number z < y is an upper bound for A. What problem would arise if there was such a number z?

[Edit] Sorry, there is a typo. The last paragraph should have read:

You have to show that no number z < x is an upper bound for A. What problem would arise if there was such a number z?
 
Last edited:


Hmm... if there were such a number z, then y could not be the least upper bound...

Could the proof go something like this?:

Choose arbitrary E>0, and let y be an upper bound of A

Suppose z is an upper bound of A, and y>z>y-E.

y is not the lub

does this finish the proof?
 


ssayan3 said:
Hmm... if there were such a number z, then y could not be the least upper bound...

Could the proof go something like this?:

Choose arbitrary E>0, and let y be an upper bound of A

Suppose z is an upper bound of A, and y>z>y-E.

y is not the lub

does this finish the proof?

No. Sorry, but I had a typo which I have corrected. Read my reply and try again.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top